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Chemistry 19 Online
OpenStudy (anonymous):

What is the limiting reactant when 4.5 moles of aluminum react with 6.7 moles of oxygen gas? unbalanced equation: Al + O2-->AL2O3

OpenStudy (anonymous):

Al.

OpenStudy (anonymous):

Could you please explain how you got Al as the limiting reactant? if it's not any trouble.

OpenStudy (anonymous):

I aprreciate the response, but an explanation along with it would suffice.

OpenStudy (anonymous):

@NoDino

OpenStudy (anonymous):

Sorry! i had gone out, uhm, let me see here.

OpenStudy (anonymous):

Well, when you look 4.5 moles of aluminum react with 6.7 moles of oxygen gas and the equation Al + O2-->AL2O3 it is 1 mole of Al reacts with 1 mole of O2 because there is nothing before the Al or O2, meaning the ratio is 1:1 Therefore you will run out of Al before you do O2. But! If it were like this (Al + 3O2-->AL2O3) the ratio would be 3:3. In which you would run out of O2 before Al.

OpenStudy (anonymous):

@Patsfan12

OpenStudy (anonymous):

Thank you so much!

OpenStudy (anonymous):

No problem.

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