What is the limiting reactant when 4.5 moles of aluminum react with 6.7 moles of oxygen gas? unbalanced equation: Al + O2-->AL2O3
Al.
Could you please explain how you got Al as the limiting reactant? if it's not any trouble.
I aprreciate the response, but an explanation along with it would suffice.
@NoDino
Sorry! i had gone out, uhm, let me see here.
Well, when you look 4.5 moles of aluminum react with 6.7 moles of oxygen gas and the equation Al + O2-->AL2O3 it is 1 mole of Al reacts with 1 mole of O2 because there is nothing before the Al or O2, meaning the ratio is 1:1 Therefore you will run out of Al before you do O2. But! If it were like this (Al + 3O2-->AL2O3) the ratio would be 3:3. In which you would run out of O2 before Al.
@Patsfan12
Thank you so much!
No problem.
Join our real-time social learning platform and learn together with your friends!