The position of an object at time t is given by s(t) = -9 - 3t. Find the instantaneous velocity at t = 8 by finding the derivative.

Question

agreene · Answer

find $s'(t)$  it's pretty straightforward

anonymous · Answer

-33?

agreene · Answer

no,
$$\frac{d}{dt}-9-3t $$
-9 goes to 0 (no t)
-3t goes to -3 (remove 1 t per d/dt)
so $$s'(t)=-3$$

anonymous · Answer

i just plugged it in, i didnt to the derivative.... im dumb

agreene · Answer

lol, it happens

anonymous · Answer

can you help me with some more questions?

agreene · Answer

sure

anonymous · Answer

Use graphs and tables to find the limit and identify any vertical asymptotes the function.

anonymous · Answer

http://gyazo.com/0a2950b35dfd6f89f7989cf3a48b4271

anonymous · Answer

im thinking it is 0 for the limit

agreene · Answer

no, if you think about it. as  $x \rightarrow 10$ that denominator is going to -> 0
if you have anything divided by 0 it's gonna be bad

agreene · Answer

So, we are gonna have a vertical asymptote at x=10

agreene · Answer

it says you can use a table to find the limit, so take the function and plug in a number really close to 10 on both sides and see what happens.
9.9999999   and 10.00001  for example

anonymous · Answer

.001 and .01?

anonymous · Answer

wait they are the same

agreene · Answer

they should be large numbers.

anonymous · Answer

10 and 10

agreene · Answer

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