Question

Xavier is riding on a Ferris wheel at the local fair. His height can be modeled by the equation H(t) = 20cosine of the quantity 1 over 15 times t + 30, where H represents the height of the person above the ground in feet at t seconds.

Part 1: How far above the ground is Xavier before the ride begins?
Part 2: How long does the Ferris wheel take to make one complete revolution?
Part 3: Assuming Xavier begins the ride at the top, how far from the ground is the edge of the Ferris wheel, when Xavier's height above the ground reaches a minimum?

You must show all work.

Answer 1

\[h(t)=20\cos \(\frac{ \pi }{ 15 }t)+30\]

Answer 2

@campbell_st

Answer 3

@JFraser

Answer 4

solve for t=0 for part 1, that's simple enough

Answer 5

-20+30

Answer 6

@JFraser

Answer 7

10

Answer 8

correct? @JFraser

Answer 9

why is it -20? doesn't the equation have a positive 20?

Answer 10

cos=-1?

Answer 11

if t=0, what's \(\frac{\pi}{15} * 0\)?

Answer 12

0

Answer 13

then what's the cosine of zero

Answer 14

0 haha

Answer 15

so....

Answer 16

so 50?

Answer 17

50

Answer 18

50 feet before ride begins?

Answer 19

yes

Answer 20

ok, move onto part two? :)

Answer 21

how many degrees make up a full revolution of a circle?

Answer 22

360

Answer 23

is there a place in the formula to put an angle?

Answer 24

i dont think so

Answer 25

pi is your place for an angle

Answer 26

insert 360 in for pi?

Answer 27

yes

Answer 28

what about t

Answer 29

20cos(24t)+30

Answer 30

you're solving for t, because it's asking for time

Answer 31

can you help me solve?

Answer 32

@phi

Answer 33

@phi can you please help me?

Answer 34

@jdoe0001

Answer 35

@Australopithecus

Answer 36

@SolomonZelman

Answer 37

@tester97

Answer 38

@nincompoop

Answer 39

Step by step solution
http://www.mathskey.com/question2answer/16927/help-please-thank-you