Question

anyone there can help me

Answer 1

\[\int\limits_{}^{} \sqrt{x} \ln 2xdx \]

Answer 2

By parts

\[u = \ln2x~~~du=\frac{ 1 }{ x }dx\]
\[dv = \sqrt{x} dx~~~ v = \frac{ 2x ^{3/2} }{ 3 }\]

Answer 3

i dont know about by parts ser advance assignments

Answer 4

can u help me

Answer 5

I don't know what ser advance assignments are.

Answer 6

no no no this is my advance assignment

Answer 7

I can only think of this using integration by parts

Answer 8

\[\int\limits u dv = uv - \int\limits v du\]

Answer 9

Try to apply the integration by parts formula that batman has showed you above.
Give it a try?

Answer 10

ok thanks
:D