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Mathematics 18 Online
OpenStudy (anonymous):

What function accurately represents the sine curve for indigo light?

OpenStudy (anonymous):

OpenStudy (anonymous):

f(x) = sin 430πx f(x) = sin 215πx f(x) = sin pi over 215x f(x) = sin pi over 430x

jimthompson5910 (jim_thompson5910):

430 nm is the wavelength

jimthompson5910 (jim_thompson5910):

aka it's the period of that trig function

jimthompson5910 (jim_thompson5910):

every 430 nm, it will repeat itself

jimthompson5910 (jim_thompson5910):

Period: T = 2pi/B 430 = 2pi/B 430B = 2pi B = 2pi/430 B = pi/215

OpenStudy (anonymous):

im sorry i dont follow

jimthompson5910 (jim_thompson5910):

in general, we have this trig equation y = A*sin(Bx - C) + D

jimthompson5910 (jim_thompson5910):

the period of that function is T = 2pi/B

jimthompson5910 (jim_thompson5910):

T is the period and B is from y = A*sin(Bx - C) + D

jimthompson5910 (jim_thompson5910):

So that's why the function is \[\Large f(x) = \sin\left(\frac{\pi}{215}x\right)\]

OpenStudy (anonymous):

ill study your work a bit more so i fully understand, thank you so much, this helped a lot!

jimthompson5910 (jim_thompson5910):

you're welcome

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