Is the instantaneous rate of change of f at x=4 greater than the rate of change at x=6? Justify.
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do I use x=2 and x=6 to determine instantaneous rate of change of f at x=4?
that will give you the average rate of change
ok, now I really don't know what to do since it states rate of change at x=6 (second part)
then I can use x=2 and x=4 for instantaneous rate of change of f at x=4 or I can use x=4 and x=6
I guess the best thing you can do is average the two average rates of change around x = 4 to get an approximation of the instantaneous rate of change
really, I don't think I have seen that done on AP calculus but I could be wrong
me neither, but idk what else to do you're given a discrete data set when you should be given a continuous function
If a function is differentiable then it is continuous, correct? My instructions above the table state: Consider the values of a differentiable function, f(x), is the table below to answer the questions that follow.
that is true, but you need to be able to get very very close to x = 4 to get the instantaneous rate of change at x = 4
so the best you can do is do an approximation
ok, how about the part of "the rate of change at x=6"? what do you suppose they mean by that?
maybe this is just a bad worksheet.......
here's what I get when I plot the points
I guess I am trying to figure out the purpose of this worksheet. It is not flowing for me.....
I think what you need to do is find these two slopes BC & CD then average those two slopes to get the approximate instantaneous rate of change
maybe I should just trash this worksheet
ok maybe the second page is not so bad, care to see if it makes sense with me
Consider f(x), does Rolle's Theorem apply on the following interval? [2,14] and [2,8] Explain why or why not
I know that Rolle's Theorem basically states that that the instantaneous rate of change is zero. (ie horizontal tangent) or f ' (x)=0
it's basically a very specialized case of the MVT
I am sure I did not do a good job of summarizing Rolle's Theorem....
it says that if f(x) is continuous on [a,b] and differentiable on (a,b) AND also f(a) = f(b), then there's a value c such that f ' (c) = 0
so for [2,14], I put yes because f ' (c)=0 at c=8 in this case also, because I could show that f(14)=f(c)=5
example |dw:1407459805408:dw|
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