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Chemistry 8 Online
OpenStudy (anonymous):

Consider the rate law below. R=k[A][B]^2 which step would quadruple the rate? doubling the concentration of A doubling the concentration of B doubling the concentration of both A and B doubling the concentration of A but halving the concentration of B @aaronq

OpenStudy (aaronq):

R=k[A][B]^2 assume you have [A]=[B]=1 rate= [1][1]^2=1 plug in the changes that they're proposing and observe how the rate changes

OpenStudy (anonymous):

True :P

OpenStudy (anonymous):

So, A?

OpenStudy (aaronq):

what did you get for the rate?

OpenStudy (anonymous):

No clue, i was guessing, im lost. haha..

OpenStudy (aaronq):

just plug in the values. If the concentraion of A doubles, then you have": rate= [2][1]^2=2 so the rate doubled but not quadrupled

OpenStudy (anonymous):

Oh! I understand what you did now So it would be C.

OpenStudy (anonymous):

I think.

OpenStudy (anonymous):

No, it would be B, [1][2]^2 = 4

OpenStudy (anonymous):

@aaronq

OpenStudy (anonymous):

Yeah, it would be B.

OpenStudy (aaronq):

yes it is B

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