Ask your own question, for FREE!
Physics 8 Online
OpenStudy (anonymous):

Hi again! So, I am having trouble with this other problem that I shall put up in a few minutes. Will also show work so please tell me what exactly I'm doing wrong! Many thanks in advanced.

OpenStudy (anonymous):

OpenStudy (anonymous):

So i am trying to calculate the binding energy which I know is given by E=mc^2. So first I could out the number of neutrons and the number of protons for Sulfer which I found to be: Neutrons: 19 Protons: 16 I then did 19(1.0087)+16(1.0073)=35.6 Then I know I am supposed to subtract this from the total mass of Sulfur which they gave me on the table as: 32.066 So I got 35.6-32.066=3.534 Then they ask for the binding energy in MeV so I know i had to multiply using the conversion factor: 3.534(931.5)=3291.921 which i know isn't the answer because it is just a huge number and I have no idea what else I'm supposed to do.

OpenStudy (anonymous):

Many thanks in advanced!

OpenStudy (anonymous):

Your issue is that you used the mass of the nuclide for normal Sulfur. The Sulfur here is an isotope S-35. There are 3 additional neutrons you are not accounting for. Instead of 32.066u, I believe you would want to use 34.969u.

OpenStudy (anonymous):

I'm sorry but I am still getting an incorrect answer. Although I do understand your point.

OpenStudy (anonymous):

Are you getting about 290-291 MeV?

OpenStudy (anonymous):

No I am not, i keep getting some really big number ->2988.72

OpenStudy (anonymous):

this is what i'm getting at least, \[\Delta m = Zm_{H} + Nm_{N} - m_{Z}^{A}\]\[\Delta m = (16)(1.007276u) + (19)(1.008665u) - 34.969u = 0.312051u\]\[BE = \Delta m c^{2}=(0.312051)(931.5) = 290.7 MeV\]

OpenStudy (anonymous):

Yes I had input that and it isn't the right answer either. I'm sorry

OpenStudy (anonymous):

Hmm, that weird. And no need to apologize. I'm sorry I couldn't get the right thing. I can't find any flaws in the work, although it has been a few years since I calculated this stuff haha. Maybe someone will spot something.

OpenStudy (anonymous):

Thank you though I really appreciate it :)

OpenStudy (joannablackwelder):

I am looking into this as I don't remember how to do it off the top of my head, but I noticed that your equations is E=mc^2 but you never squared anything. Did I miss something?

OpenStudy (anonymous):

you factor out the c^2 and then they all cancel at the end.

OpenStudy (anonymous):

I was basically following my professor's notes and i am doing the same exact thing he did and still nothing.

OpenStudy (joannablackwelder):

Ok, just checking. I will keep looking.

OpenStudy (anonymous):

I really appreciate your help

OpenStudy (joannablackwelder):

From what I can tell, @Pompei00 has the right idea that you need to use the actual mass of S-35. Otherwise, it all looks right to me.

OpenStudy (joannablackwelder):

The only thing I can think of is rounding error. Do you know what digit you are to round to?

OpenStudy (anonymous):

They use whole numbers for this one. I honestly do not know what I'm doing wrong...i've watched a few videos and googled everything, and nothing.

OpenStudy (joannablackwelder):

Ok, and you put in 291 and it was wrong?

OpenStudy (joannablackwelder):

I don't really see any errors either...

OpenStudy (anonymous):

That's okay. I'll still wait and see if someone can help me with this. THank you again :)

OpenStudy (joannablackwelder):

Ok. No worries.

OpenStudy (anonymous):

Since no ones getting answers you better ask your professor

OpenStudy (anonymous):

and please tell me from where you got your screenshot

OpenStudy (anonymous):

Haha it's okay. I'm looking over other questions as well. I got my screen shot from my computer. I took it myself.

OpenStudy (anonymous):

is it a software or a website from where u got your question

OpenStudy (anonymous):

Yep. it's required for our class. I really don't like it, in my opinion. All your answers need to be put in a specific way and it's so annoying.

OpenStudy (anonymous):

Okay then. am still trying to find the answer

OpenStudy (anonymous):

I reallly appreciate you trying to help

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!