Question

The figure below shows a trapezoid, ABCD, having side AB parallel to side DC. The diagonals AC and BD intersect at point O.

Answer 1

If the length of AO is double the length of CO, the length of DC is

half of the length of AB

one-fourth the length of DB

double the length of AO

equal to the length of OB

Answer 2

@claritamontano

Answer 3

would be half of the length AB

Answer 4

thanks

Answer 5

no problem!

Answer 6

can you help me with this one too please, sorry to bother

Answer 7

no your fine!

Answer 8

The figure below shows a square ABCD and an equilateral triangle DPC:

Answer 9

Jim makes the chart shown below to prove that triangle APD is congruent to triangle BPC:

Answer 10

Statements Justifications
In triangles APD and BPC; DP = PC Sides of equilateral triangle DPC are equal
In triangles APD and BPC; AD = BC Sides of square ABCD are equal
In triangles APD and BPC; angle ADP = angle BCP Angle ADC = angle BCD = 90° and angle ADP = angle BCP = 90° - 60° = 30°
Triangles APD and BPC are congruent SSS postulate

Answer 11

What is the error in Jim's proof?
He writes DP = PC instead of DP = PB.

He writes AD = BC instead of AD = PC.

He assumes the measure of angle ADP and angle BCP as 30° instead of 45°.

He assumes that the triangles are congruent by the SSS postulate instead of SAS postulate.

Answer 12

@claritamontano

Answer 13

would be he assumes that the angle ADP and angle NCP
one because you arent given any measurements.

Answer 14

whait so it is C?

Answer 15

yup... i think it is.

Answer 16

thanks

Answer 17

np