HELP PLEASE The figure shows three right triangles. Triangles PQS, QRS, and PRQ are similar. Theorem: If two triangles are similar, the corresponding sides are in proportion.
Using the given theorem, which two statements help to prove that if segment PR is x, then x2 = 97? Segment PR x segment PS = 16 Segment PR x segment SR = 36 Segment PR x segment PS = 36 Segment PR x segment SR = 81 Segment PR x segment PS = 16 Segment PR x segment SR = 81 Segment PR x segment PS = 81 Segment PR x segment SR = 16
@jim_thompson5910
@zepdrix
how far did you get?
i dont know, what i have to do
i think its B
@jim_thompson5910
@JoannaBlackwelder
@ganeshie8
because "Triangles PQS, QRS, and PRQ are similar" we can set up this equation PR/PQ = PQ/PS and then cross multiply to get PR*PS = PQ*PQ PR*PS = 4*4 ... replace PQ with 4 since PQ = 4 PR*PS = 16
see how I did that?
yes got it, so then what?
so its a or c
@jim_thompson5910
help please @JoannaBlackwelder @JMark @jim_thompson5910
because those triangles are similar, you can also say PR/QR = QR/SR what can you do with that info?
cross multiply?
PR*QR QR*SR? @jim_thompson5910
not quite
but yes you do cross multiply
to get PR*SR = QR*QR
then what?
then you place the numbers? look for a number to change the letters
9*9? @jim_thompson5910
so PR*SR = 81
so its C right
@jim_thompson5910
correct
can you help me with one more
@jim_thompson5910
Look at the figure shown below:
Nora is writing statements as shown to prove that if segment ST is parallel to segment RQ, then x = 45.
Statement Reason 1. Segment ST is parallel to segment RQ Given 2. Angle QRS is congruent to angle TSP Corresponding angles formed by parallel lines and their transversal are congruent. 3. Angle SPT is congruent to angle RPQ Reflexive property of angles. 4. Triangle SPT is similar to triangle RPQ Angle-Angle Similarity Postulate 5. ? Corresponding sides of similar triangles are in proportion.
Which equation can she use as statement 5? 60:x = 48:(48 + 36) 60 + x = 48 + 36 60 - x = 48 − 36 60:(60+x) = 48:(48 + 36)
@jim_thompson5910
i dont know what to do
@ganeshie8 please help
please limit to one question per post
if i post it again can you help me?
wil try, opening a new question bumps ur question in the top and makes others see it and increase ur chances of getting help quick... so... its for your good only :P
ok thanks
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