Question

find a quadratic equation that has root of 3+-i

Answer 1

For a quadratic equation, if you have one imaginary root, then you will have a second imaginary root. [Which is the conjugate of the first]

For a biquadratic equation, if you have 2 imaginary roots (which are not conjugates of each other), you'll get 2 more imaginary roots which are conjugates of the previous 2.

For a cubic polynomial, you cannot have 2 imaginary roots which are not conjugates of each other, if you have 1 imaginary root, you'll have its root as a conjugate and will have a real root.

Theorem?

Imaginary roots for polynomials always come in pairs, pairs which are conjugates of each other.

Can you find its conjugate and then find the quadratic equation, with the 2 roots you have?

Answer 2

conjugate is 3-(-i) then what?

Answer 3

x^2 +3x+10

Answer 4

how did you get that?

Answer 5

if one root is complex then other root is conjugate of that--> means if one root is 3-i then other root will be 3+i. I U use property of sum of roots and product of roots, you will get the answer

Answer 6

you should know that property first )

Answer 7

i dont...

Answer 8

There is a property..!!!