Question

What are the number of ways, when ten persons, amongst whom A, B and C are to speak at a function, where A wants to speak before B and B wants to speak before C?

Answer 1

9!

Answer 2

10P3

Answer 3

i think it should be 10!/6

Answer 4

10p3 mean number of ways you can choose 3 people from 10 people

Answer 5

do u have options ?

Answer 6

10!/3! explain

Answer 7

Here is how I interpret the question :
All 10 guests are speaking in the function, but for some reason C wants to speak after B, and B wants to speak after A.

Answer 8

without that contraint, total number of ways for arranging the speakers = \(\large 10!\)

Answer 9

yes have options

Answer 10

since the 3 guests A,B,C wants to speak in a particular order, we divide 3!

Answer 11

10P3*7!,3!7!,10!/6

Answer 12

if you divide by 3! it does not ensure the order among a,b,c

Answer 13

there are 3! ways in which you can arrange A,B,C, but u want only one particular arrangement. so you divide