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Mathematics 19 Online
OpenStudy (anonymous):

Is this right? Question on statistics and probability.

OpenStudy (anonymous):

Tamara is reviewing recent orders at her deli to determine which meats she should order. She found that of 1,000 orders, 450 customers ordered turkey, 375 customers ordered ham, and 250 customers ordered neither turkey nor ham. Based on this data, how many of the next 1,000 customers will order both turkey and ham? Show your work, and use complete sentences.

OpenStudy (anonymous):

I'm getting 575

OpenStudy (anonymous):

@Abhisar

OpenStudy (kropot72):

Let T be the event 'ordered turkey' and let H be the event 'ordered ham'. The probability that a customer ordered turkey or ham is given by: \[\large P(T \cup H)=1.00-0.25=0.75\] \[\large P(T \cup H)=P(T)+P(H)-P(T \cap H)\ .........(1)\] Plugging the known values into (1) gives: \[\large 0.75=0.45+0.375-P(T \cap H)\ ......(2)\] Now you can solve (2) to find the probability of ordering turkey and ham. Then multiply the result by 1000 to find how many of the next 1,000 customers will order both turkey and ham.

OpenStudy (kropot72):

@Allie74 Are you there?

OpenStudy (anonymous):

Sorry, so it's 75?

OpenStudy (kropot72):

Yes, you are correct.

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