Question

The vertical asymptotes(s),if any, would be:
Select one:
a. x = 2
b. x = 2 and x = –3
c. y = 2 and y = –3
d. No vertical asymptotes

Answer 1

hello satellite

Answer 2

hi

Answer 3

first we gotta factor and cancel

Answer 4

hi @iambatman

Answer 5

\[\frac{4x^2+12x}{x^2+x-6}=\frac{4x(x+3)}{(x+3)(x-2)}=\frac{4x}{x-2}\]

Answer 6

once that is done the "vertical asymptote" is easy to find
set
\[x-2=0\] get \[x=2\]

Answer 7

a rarely seen A is your answer

Answer 8

so factor and cancel

Answer 9

then it was easy from there haha