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Algebra 18 Online
OpenStudy (anonymous):

he horizontal asymptote(s), if any, would be: Select one: a. y = 4 and y = 0 b. eq_f7749a.gif c. y = 4 d. No horizontal asymptotes

OpenStudy (anonymous):

OpenStudy (acxbox22):

what is choice B

OpenStudy (anonymous):

What makes the numerator 0 ?

OpenStudy (anonymous):

oh one sec

OpenStudy (anonymous):

B. y=1/4

OpenStudy (anonymous):

man i could swear we just did this one right?

OpenStudy (anonymous):

yes its the same equation different question

OpenStudy (anonymous):

ooh i see horizontal asymptote, not vertical

OpenStudy (acxbox22):

if i am right the horizontal asymptote is y=0

OpenStudy (anonymous):

once we have \[\frac{4x}{x-2}\] we see that the degrees are the same

OpenStudy (anonymous):

that means the horizontal asymptote is the ratio of the leading coefficients, namely \(y=4\)

OpenStudy (acxbox22):

@satellite73 isnt the horizontal asymptote y=0

OpenStudy (acxbox22):

A rational function in the form \[y=\frac{ a }{ x-b }+c\] has a vertical asymptote at the excluded value, or x = b , and a horizontal asymptote at y = c .

OpenStudy (acxbox22):

@satellite73

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