Question

the hole in the graph, if any, would be at:
Select one:
a. x = 3
b. x = –3
c. y = 3
d. No holes in the graph

Answer 1

different equation satellite

Answer 2

lol

Answer 3

this one was \(\frac{4x}{x-2}\) right?

Answer 4

yes

Answer 5

\[\frac{4x^2+12x}{x^2+x-6}=\frac{4x(x+3)}{(x+3)(x-2)}=\frac{4x}{x-2}\]

Answer 6

since the \(x+3\) cancelled the hole is at \(x=-3\)