In the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl, if 6 moles of FeCl2 are added to 6 moles of NaOH, how many moles of NaOH would be used up in the reaction?
6 moles?
3?
it'd be great if someone could help
since the equation is already balanced, what's the mole ratio of FeCl2 : NaOH?
i dont know
i think the answer's 6.
what are the coefficients in front of the FeCl2 and the NaOH?
1 and 2
so every time 1 unit of FeCl2 is used, how many units of NaOH will also be used?
2
In this case, you're starting with 6 of each of them. Will you use all 6 of both of them? No, one is going to run out first.
idk i guess so
In the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl, if 6 moles of FeCl2 are added to 6 moles of NaOH, how many moles of NaOH would be used up in the reaction? A. 6 B. 1 C. 3 D. 2
3 is for fecl2 i think
and since its 2, i think its 6 sinze 2x3 =6
so is it 6?
all 6 of the NaOH will be used, but only 3 of the FeCl2 will be used, you are correct
but now i think you have a better understanding why
thanks. i get it now. since it was 1 and 2 ratio
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