Question

What trigonometric function represents the graph?

Answer 1

Try this

http://learn.flvs.net/webdav/assessment_images/educator_algebra2_v13/10_10_part1/10_10_2.jpg

Answer 2

@OOOPS

Answer 3

<img src=" http://learn.flvs.net/webdav/assessment_images/educator_algebra2_v13/10_10_part1/10_10_2.jpg " alt="trig graph with points at 0, negative 4 and pi over 2, 0 and pi, 4 and 3 pi over 2, 0 and 2 pi, negative 4 and 5 pi over 2, 0 and 3 pi, 4"/>

Answer 4

what a mess.

Answer 5

http://learn.flvs.net/webdav/assessment_images/educator_algebra2_v13/10_10_part1/10_10_2.jpg

Answer 6

Did it go through?

Answer 7

Ohhhhh- The file is locked or something. That's messed up

Answer 8

Yes! It worked I think

Answer 9

@OOOPS

Answer 10

Answer Choices

f(x) = 4 sin(x − pi over 2)

f(x) = 4 cos(x − pi over 2)

f(x) = 4 sin(x − pi over 2) + 1

f(x) = 4 cos(x − pi over 2) + 1

Answer 11

How did you get to that? I believe you, I just want to know for my exams

Answer 12

Oh, I am sorry, It's the first one f(x) = 4sin(x-pi/2)

Answer 13

Ok

Answer 14

https://www.desmos.com/calculator/6lnme6ncsr

Answer 15

Thank you!

Answer 16

In this site, to save time or to make sure the answer is correct, I use math tool like demos or wolfram.
However, if you need the logic, I can guide you . Want it?

Answer 17

Well- not really. I've been working on this since four and my mind won't absorb anything anyways. However, I do have another question, where I would like the logic. Do you think you could help me?

Answer 18

I can't say anything until I see the question

Answer 19

Simplify square root parenthesis 1 minus sine theta parenthesis times parenthesis 1 plus sine theta parenthesis

Answer 20

oof- that's difficult to decipher

Answer 21

\[\sqrt{(1-sin\theta)(1+sin\theta)}\]
right?

Answer 22

That's amazing

Answer 23

\[(\color{red}{a}~-~\color{blue}{b})~~~(\color{red}{a}+~~\color{blue}{b})=~~~~\color{red}{a^2}-\color{blue}{b^2}\\(\color{red}{1}-\color{blue}{sin\theta})(\color{red}{1}+\color{blue}{sin\theta})=\color{red}{1^2}-\color{blue}{sin^2\theta}=cos^2\theta\]
now, put it under the squareroot \(\sqrt{cos^2\theta}=??\)

Answer 24

\[\cos \theta \]

Answer 25

that'sit

Answer 26

±sin Θ

|cos Θ|

±tan Θ

square root sine theta

Answer 27

It would be the second one?

Answer 28

\[\sqrt{(1-sin\theta)(1+sin\theta)}=\sqrt{cos^2\theta} =cos\theta\]

Answer 29

yup

Answer 30

But you get the logic, right?

Answer 31

Yes, I do, thank you! I have 1 last question- It's another graph. Based on the answers I think it's pretty simple.

Answer 32

Would you mind helping?

Answer 33

What function accurately represents the sine curve for indigo light?

Answer 34

I think it is \(sin (\dfrac{\pi}{215}x)\)
do you have any choice like this??

Answer 35

f(x) = sin 430πx

f(x) = sin 215πx

f(x) = sin pi over 215x

f(x) = sin pi over 430x

Answer 36

That looks like C

Answer 37

I'm going for it. Thank you so much for all of your help!!!

Answer 38

ok