Question

What is the simplified form of the expression sqrt(16c^8) - (c^2) + 5 sqrt(c~2) + (4c^2)

Answer 1

@iPwnBunnies

Answer 2

Simplify the expressions in the square root, first.

Answer 3

ok ;3

Answer 4

\[\sqrt{16c^{8}} = \sqrt{4*4*c^{4}*c^{4}} = 4c^{4}\]

Answer 5

ok i got it

Answer 6

\[5 \sqrt{c^{2}} = 5c\]
Now, combine like terms. c:

Answer 7

do i just add them all together?

Answer 8

Yes, that's what combine like terms are. :3
But remember, you can only add variables of a similar power.
So, you can't add c^4's and c^2's together.

Answer 9

ok ;L

Answer 10

Now we have: \[4c^{4} - c^{2} + 5c + 4c^{2}\]

Answer 11

Add similar terms. The c^2 terms will combine, in this case. :3

Answer 12

yes

Answer 13

4c^2+5c+3c^2?

Answer 14

Yesh. c:

Answer 15

oh

Answer 16

so thats the answer?

Answer 17

That is the simplified form of the expression. o-o

Answer 18

hmmm

Answer 19

Unless you can factor out a whole number, which you can't. The coefficents of the variables don't share a common factor.

Answer 20

A) 8c4 + 8c
B) 4c4 + 8c
C) 8c4 + 6c
D) 4c4 + 6
;P;P;P;P;P;P;P;P;P

Answer 21

hmmmmmmm

Answer 22

from my opinion its either c or d

Answer 23

cause thats the only logical answer

Answer 24

Did you write the problem out correctly?

Answer 25

i have nooo idea

Answer 26

o-o

Answer 27

\[\sqrt{16c ^{8}}-\sqrt{c ^{2}}+5\sqrt{c ^{2}}+\sqrt{4c ^{2}}\]

Answer 28

there ;P

Answer 29

is that better? or does it make it more confusing?

Answer 30

Ahh, there we go. ^.^
Again, simplify the square roots. Eliminate them. :3

Answer 31

ooo

Answer 32

so does it become the same answer?

Answer 33

No, you left out a few square roots in the problem you originally posted.

Answer 34

oh........

Answer 35

Can you not do the work? Simplify square roots? o-o

Answer 36

NUUUUUUUUUUUUUUUUU~~~~~~!!!!!!!!! 0O0'

Answer 37

\[\sqrt{c^2} = \sqrt{c*c} = c\]
There are two c's being multiplied under a square root. You can pull them both out, and it just becomes c.

Answer 38

4c^4

Answer 39

yeah i know that one

Answer 40

Mhm, go on. :3

Answer 41

problem is can you add the sqrt(4c^2) with the other c^2 thing

Answer 42

you can't right?

Answer 43

and then the last one is 2c right?

Answer 44

You can only add square roots when the thing under the radical is the same.
For example:
\[5\sqrt{x^{2}} + 2\sqrt{x^{2}} = 7\sqrt{x^{2}}\]

Answer 45

Yes, last one is 2c.. c:
NOW, combine like terms again. It'll be a nice answer.

Answer 46

yay!

Answer 47

answers op!

Answer 48

thanks i got it ;P so it was D

Answer 49

my prediction was correct, i am better than SH!

Answer 50

MWAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA!

Answer 51

o_o

Answer 52

can i also ask you another question tho?

Answer 53

Sure.

Answer 54

\[2\sqrt{10k}\times5k \sqrt{2}\]

Answer 55

there ;3

Answer 56

hmmmmmm

Answer 57

When multiplying radicals, multiply the stuff outside the radicals.
Then, multiply the stuff inside the radicals, and put that product under another radical.

Answer 58

ok

Answer 59

And then you can simplify what's under the radical even more, in this problem.

Answer 60

but

Answer 61

how do i multiply whats inside the radicals

Answer 62

do i multiply 10k and2?

Answer 63

10k is one factor. 2 is the other factor. o-o
Yes

Answer 64

so i X it together?

Answer 65

Yesh.

Answer 66

which makes 20k

Answer 67

then 10k?

Answer 68

which is \[10k \sqrt{20k}\]

Answer 69

Correct. c:
Can you simplify the square root now?

Answer 70

hmmm

Answer 71

2k?

Answer 72

tooshay?

Answer 73

;3

Answer 74

Nope. :3 You can't pull out a 'k' from the square root if there's only 1 'k' under the square root.

Answer 75

\[\sqrt{20k} = \sqrt{4*5*k} = \sqrt{2*2*5*k}\]

Answer 76

20k sqrt5

Answer 77

5k

Answer 78

Yesh. ^-^

Answer 79

hooray!

Answer 80

\[\sqrt{2}(6b \sqrt{t}-5)\]

Answer 81

oops not 6b

Answer 82

Distribute the sqrt(2) to each term.

Answer 83

sqrt(2) (8sqrt(t)-5)

Answer 84

\[8\sqrt{2t}-5\sqrt{2}\]

Answer 85

You got it. ^--^

Answer 86

yay!

Answer 87

do i add sqrt's together?

Answer 88

Wow all of this instead of going here. http://bit.ly/1q1JkSH

Answer 89

like sqrt(2) and sqrt(16)

Answer 90

so

Answer 91

do i add the sr together? or multiply them?

Answer 92

You can only add them if the stuff under the radical is the same.

Answer 93

so its 18?

Answer 94

Nooo. You can't add those together.
Only if terms SHARE the same square root 'stuff', you can add them.
I showed you earlier.
\[5\sqrt{2x} + 4\sqrt{x} + 2\sqrt{2x} = 6\sqrt{2x} + 4\sqrt{x}\]
As an exmaple

Answer 95

Omg. 5+2 = 7, not 6. ._.

Answer 96

OH NO

Answer 97

ThE MATHLETE MADE A MISTAKE THE WORLDS GONNA DIE!

Answer 98

AHHHHWUDFUSVJGEFHUIWKSCJBHJFEWKYIR#$'"()EQODUISVHGYU#R"E