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Mathematics 20 Online
OpenStudy (hkmiu):

Write the given function as the composite of two functions, neither of which is the identity function, f(x) = x http://media.education2020.com/evresources/649-03-02-00-00_files/i0270001.jpg

OpenStudy (australopithecus):

A composite function is just one function contains another function let s(x) and g(x) be separate functions. Notation of composite functions is, (s o g)(x) is the same as s(g(x)) (g o s)(x) is the same as g(s(x)) for example given s(x) = 1 + x and g(x) = x^2 (s o g)(x) = s(g(x)) = 1 + x^2 and (g o s)(x) = g(s(x)) = (1 + x)^2

OpenStudy (australopithecus):

you should be able to solve this now

OpenStudy (australopithecus):

This is actually good practice if you ever get into calculus, as it can make taking derivatives a lot easier.

OpenStudy (hkmiu):

I'm actually really confused lol. My teacher just threw this at me. But thanks, imma sit here and give some thoughts on it hahaa

OpenStudy (australopithecus):

It is pretty simple actually dont fret, look at my example, (g o s)(x) = g(s(x)) = (1 + x)^2 see a similarity between this composition and your function?

OpenStudy (australopithecus):

hint: \[\sqrt{x} = x^{\frac{1}{2}}\]

OpenStudy (australopithecus):

\[\sqrt[3]{x} = x^{\frac{1}{3}}\] essentially, \[\sqrt[n]{x} = x^{\frac{1}{n}}\] where n is just a number

OpenStudy (australopithecus):

just to explain this notation just incase you didnt understand it

OpenStudy (australopithecus):

I will do a few more examples maybe that will help, let, g(x) = 2 and f(x) = x then, (f o g)(x) = f(g(x)) = 2 another example let c(x) = x^(1/2) and d(x) = 1 + x then, (c o d)(x) = c(d(x)) = (1+x)^(1/2)

OpenStudy (australopithecus):

its like subing a number in but instead you are subing in another function

OpenStudy (australopithecus):

You just need to think about how this function can be split into two functions

OpenStudy (australopithecus):

My last example is very very similar to your problem

OpenStudy (australopithecus):

if you make a guess I can tell you if you are on the right track

OpenStudy (australopithecus):

Just a final note in this problem you are just doing the reverse you are starting wtih a function then devise what two functions one subbed into the other make it up so, f(x) = (g o s)(x) = g(s(x)) = (x^2 + 2)^(1/3) we need to come up with what g(x) and s(x) are to answer this question

OpenStudy (hkmiu):

Okay so I don't know if I'm even doing this right but I got something close to f(x) = sqrt(x+2) g(x)= x but something is missing

OpenStudy (hkmiu):

omg no i forgot the about thr ^(1/3)

OpenStudy (australopithecus):

yes you did :)

OpenStudy (australopithecus):

You are close but I feel like a teacher wouldnt give you full marks because you can sub any function into g(x) = x or vice versa and get the same function back. you arent creating two distinct functions from the single function (f o g)(x) = (x + 2)^(1/3)

OpenStudy (australopithecus):

you are very close though

OpenStudy (australopithecus):

think of it as an inner and outer function

OpenStudy (australopithecus):

look at my examples again briefly you are on the right track though

OpenStudy (australopithecus):

essentially change g(x) = x to the outer function and f(x) to the inner function

OpenStudy (australopithecus):

for example, in the function (x + 1)^5 x + 1 is the inner function x^5 is the outer function

OpenStudy (australopithecus):

if you sub x + 1 into x^5 you get the function (x + 1)^5

OpenStudy (hkmiu):

i'm just confused on how to do the ^(1/3)

OpenStudy (australopithecus):

its just another exponent nothing special

OpenStudy (hkmiu):

wait so (sqrt(x+2))^2 ???

OpenStudy (australopithecus):

if you did that, \[\sqrt{x+2}^{2} = ((x+1)^{\frac{1}{2}})^2 = (x+1)^\frac{2}{2} = x + 1\]

OpenStudy (hkmiu):

f(x) = (x+2)^(1/3) g(x) = x^2

OpenStudy (australopithecus):

you need to include the composite how are you subing one function into the other to get the one you are looking for

OpenStudy (hkmiu):

like (fog)(x) ??

OpenStudy (australopithecus):

if you did that would you get the function you are looking for??

OpenStudy (australopithecus):

Another example, again, split into an inner and outer function (5 + x)^(1/5) we see that 5+x is an inner function we see that x^(1/5) is the outer function we sub the inner function into the outer function and we get (5 + x)^(1/5)

OpenStudy (australopithecus):

this example is pretty much exactly the same as your problem

OpenStudy (hkmiu):

whaaaaaaaaaaaaa :o so it could also be f(x) = ^(1/3) g(x) = x^2 +2 ????????????

OpenStudy (australopithecus):

yes!!!

OpenStudy (australopithecus):

g(x) is your inner function f(x) is your outer function

OpenStudy (hkmiu):

whaaaaaaaaaaaaaaa :o how am i doing this omg

OpenStudy (hkmiu):

thanks so much!!

OpenStudy (australopithecus):

I think you understand?

OpenStudy (hkmiu):

Yeah, I think I understand lol....

OpenStudy (australopithecus):

now write the composite

OpenStudy (australopithecus):

If the outer function is subbed into the inner function you will get the answer wrong, so you have to use composite notation

OpenStudy (australopithecus):

to show your final answer

OpenStudy (hkmiu):

(f o g) is right??

OpenStudy (australopithecus):

yes f(g(x)) is correct, I like to think of it as f is eating g to remember the notation where the circle is a mouth but I'm weird

OpenStudy (hkmiu):

yasssss ^.^ thank you!!

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