I have a couple of practice problems that i need help in ! medals!
Graph the hyperbola with equation
my options
@ganeshie8
I remember once in my lifetime, I studied these things and now I have become rusty over these topics, so I fully give this responsibility to @ganeshie8 .
:)
Or other useful and helping members may help here.. :)
@ganeshie8 don't tell me you are also like me... :P
i think eliminating few options based on `center` would be a good place to start
i forgot the actual method to work these haha! from the equation it seems the center is definitely NOT (0, 0) - based on just this info which two options can u eliminate @mondona ?
B and C (:
Perfect !
any ideas on how to decide whether its A or D ?
i have no idea :(((((((
let me look in my book again
Notice that A is standing straight UP-DOWN and D is sleeping LEFT-RIGHT
yes i see that
\[\frac{ (x-h)^2 }{ a^2 }-\frac{ (y-k)^2 }{ b^2 }=1\] This is a horizontal (x term is positive) hyperbola for vertical the equation looks like this, \[\frac{ (y-k)^2 }{ a^2 }-\frac{ (x-h)^2 }{ b^2 }=1\] where your center is (h,k)
so my answer would be D
Yeah Batman is saying right.. He can't do unfair with the people of Gautham City(Openstudiers.. :)
D is \(\large \color{Red}{\checkmark }\)
Yes, D is correct. Just to add a bit more information, a = transverse semi - axis (positive denominator), distance from centre to vertex. b = conjugate semi - axis (the negative denominator). c = distance from centre to focus. (Always largest) So if you had this, |dw:1407590003406:dw| this is essentially what's going on in an horizontal hyperbola, these things are quite neat, also remember for the hyperbola only: c^2=a^2+b^2. I could give you more examples but Idk if you're interested or not haha, I personally find them quite neat.
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