Question

Jane bought a car for $30,303. The value of the car depreciated at a constant rate per year. The table below shows the value of the car after the first and second years:

Year
1

2
Value (in dollars)
25,757.55

21,893.92


Which function best represents the value of the car after t years?

f(t) = 25,757.55(0.85)t

f(t) = 30,303(0.85)t

f(t) = 30,303 (0.15)t

f(t) = 25,757.55 (0.15)t

Answer 1

@FriedRice

Answer 2

@waterineyes @study100 @paki @Blink-182 @nikato

Answer 3

Will medal and fan <3

Answer 4

Oh....gosh, I honestly don't have a clue..hang on

Answer 5

Alrighty! :) Ill be here!

Answer 6

@camerondoherty

Answer 7

So the value started out at 30,303 so f(0)=30,303 f(1) = 25,757.55 and f(2)=21,893.92.

Answer 8

So After 1 year the car depricated by $4545.45. Since it decreases by a constant rate every year it decreases by the same amount. $4545.45

Answer 9

I think its B...but she sounds a bit more on spot so I'd go with camerondoherty on this

Answer 10

4545.45 is 15% of 30,303 or 0.15

Answer 11

This is how ill do this....
With functions, the first inititial price should be included so that leaves you between B and C

Then just plug 2 for t in both and see which one gives you 21893.92

Answer 12

i think C is d ans

Answer 13

I think its C?

Answer 14

Since we know f(0)=30,303 f(1)=25,757.55 and f(2)=21,893.92 try to find f(2). It is by 15% so I would say try to find f(2) in C and see if it matches the exact value

Answer 15

AM I right?

Answer 16

Well, See for yourself... Substitute t for 2 in the equation and solve and see if you get 21,893.92

Answer 17

Ok, that didnt work, so its B.

Answer 18

@camerondoherty

Answer 19

Yes. b is correct

Answer 20

Would you help me with a couple more?

Answer 21

Sure. I'll try