Question

determine the midpoint of the segment joining the given two points
1. (3a-1, a) and ( 5a+5, -a )

Answer 1

@jdoe0001 what about this??

Answer 2

\(\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 3a-1}}\quad ,&{\color{blue}{ a}})\quad &({\color{red}{ 5a+5}}\quad ,&{\color{blue}{ -1}})
\end{array}\quad
\left(\cfrac{{\color{red}{ (5a-5)}} + {\color{red}{(3a-1)}}}{2} , \cfrac{{\color{blue}{ -a}} + {\color{blue}{ a}}}{2} \right)\)

Answer 3

hmmm I have an -1 there =) anyow.. just a typo

Answer 4

\(\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 3a-1}}\quad ,&{\color{blue}{ a}})\quad &({\color{red}{ 5a+5}}\quad ,&{\color{blue}{ -a}})
\end{array}\qquad
\left(\cfrac{{\color{red}{ (5a-5)}} + {\color{red}{(3a-1)}}}{2} , \cfrac{{\color{blue}{ -a}} + {\color{blue}{ a}}}{2} \right)\)

Answer 5

,, would the answer be (8a-4)/2 and 0?

Answer 6

well... \(\bf \left(\cfrac{{\color{red}{ (5a-5)}} + {\color{red}{(3a-1)}}}{2}\quad ,\quad \cfrac{{\color{blue}{ -a}} + {\color{blue}{ a}}}{2} \right)\implies \left(\cfrac{8a-6}{2}\quad ,\quad 0\right)\)

Answer 7

its 5a+5

Answer 8

ohh shoot.. it's =(

Answer 9

then yes :) is \(\bf \left(\cfrac{{\color{red}{ (5a+5)}} + {\color{red}{(3a-1)}}}{2}\quad ,\quad \cfrac{{\color{blue}{ -a}} + {\color{blue}{ a}}}{2} \right)\implies \left(\cfrac{8a-4}{2}\quad ,\quad 0\right)\)

Answer 10

wait ah sec dohh darn

Answer 11

thanks , still have questions , :3

Answer 12

\(\bf \left(\cfrac{{\color{red}{ (5a+5)}} + {\color{red}{(3a-1)}}}{2}\quad ,\quad \cfrac{{\color{blue}{ -a}} + {\color{blue}{ a}}}{2} \right)\implies \left(\cfrac{8a+4}{2}\quad ,\quad 0\right)\)

+5-1 = +4