help in creating a perfect square trinomial
x^2-5x+k
I've been trying every number, but I can't seem to figure out a number that will make it a perfect square tronimal
what is half of -5?
it's -2.5
yes, now square (-2.5)^2
btw, you can also write that as -5/2
I'm sorry but I don't understand how I will square it. Like why is that necessary?
when you square (-2.5)^2 = (-2.5)(-2.5) = 6.25 or same as (-5/2)(-5/2) = 25/4 then x^2 -5x + (25/4) >> hence, k= 25/4 --------------------------------- Let's check \[(x-\frac{5 }{ 2})^2\] remember to factor this, you use x^2 +2ab +b^2 \[= x^2 +(2)(1) \frac{ -5 }{ 2 }x + \frac{ 25 }{ 4 }\] \[= x^2 -5x + \frac{ 25 }{ 4 }\]
aaaah ok. so then that concludes that K will be 25/4
to answer your question, remember when you factor (a+b)^2 = a^2 + 2ab +b^2 similar to x^2 -5x +k -------------- when you compare those two equations x^2 = a^2 a=1, since x does not have a number infront, (for ex. if 3x^2 ,then a=3 // if 4x^2, then a=4, etc.) 2ab= -5x >>plug in a=1 2(1)b= -5x b= -5/2 now, k= b^2 k= (-5/2)^2 k= 25/4= 6.25 This is just working backwards with the equation.
hope this helps :)
@study100 ah ok, thank you, i appreciate your time to help me out:)
you're welcome! Concepts > right answer.
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