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OpenStudy (anonymous):
OpenStudy (anonymous):
Thermodynamics
OpenStudy (anonymous):
For this I have to study Thermodynamics for you.. :)
OpenStudy (anonymous):
thans :D
OpenStudy (anonymous):
What thans?? And I am not going to study that... :P
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OpenStudy (anonymous):
@jim_thompson5910 good at thermodynamics?
OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
Can you help me to him?? Whom to whom??
OpenStudy (anonymous):
to jim :)
OpenStudy (anonymous):
I did not study this subject when there was time.. :) Now there is time but again no mood of studying it.. :P
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OpenStudy (agreene):
if I remember correctly you should be using \[q + (h_{in} +0.5c^2_{in}) – (h_{out}+0.5c^2_{out}) =0\]
where:
\(q\)=heat transferred per unit mass
\(h_{in}\)= specific enthalpy of inlet fluid
\(h_{out}\)= specific enthalpy of outlet fluid
\(c_{in}\)= velocity of inlet fluid
\(c_{out}\)= velocity of outlet fluid
OpenStudy (anonymous):
and then sir?
OpenStudy (agreene):
\[\rho_{in}*c_{in}*A_{in}=\rho_{out}*c_{out}*A_{out}\\p=\rho R T\]
And you can reorganize the 1st i posted to this: \[q + (h_{in} - h_{out}) + 0.5(c^2_{in} – c^2_{out}) =0\]
OpenStudy (agreene):
\(A\)= section area
\(ρ\)=density
\(p\)=pressure
\(R\)=specific gas constant
\(T\)=temperature