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Mathematics 15 Online
OpenStudy (anonymous):

3 sin(x-pi/5) =0

OpenStudy (anonymous):

using the sum and difference identities i get 0=3sin(x-pi/5)=\[3\sin(x)\cos(\pi/5)-3\cos(x)\sin(\pi/5)\]

OpenStudy (anonymous):

solve for cos(pi/5) and sin(pi/5) in your calculator., and you may be able to figure it out from there.

OpenStudy (anonymous):

x is pi/5 though...?? i think because 3sin(pi/5-pi/5)=0

OpenStudy (anonymous):

are the answers supposed to be between 0 and 2pi?

OpenStudy (anonymous):

ok so then if pi/5 is our reference angle and x has to be positive since were subtracting pi/5, in each of the we have to find the reference angle in quadrants 1 and 2 we have x=pi/5 x= pi-pi/5=4pi/5

OpenStudy (anonymous):

but 3sin(pi) also = 0. so 6pi/5 - pi/5 = pi

OpenStudy (anonymous):

\[3\sin \frac{ x-\pi }{ 5 }=0\] \[\sin \frac{ x-\pi }{ 5 }=0\] \[put \frac{ x-\pi }{ 5 } = t\] \[\sin t = 0\] \[t=0, \pi, 2\pi...... \] \[\frac{ x-\pi }{ 5 }=0, \pi , 2\pi......\] \[x-\pi=0,5\pi,10\pi.....\] \[0 \le x \le2\pi , x=\pi\]

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