Find the equation of a circle (standard form)with radius 3 that contains the points (-1,2) and (-1,8)

Question

anonymous · Answer

@UnkleRhaukus

anonymous · Answer

@sidsiddhartha

mrnood · Answer

first - how far apart are the 2 points?

What does that tell you about them on a circle radius 3?

anonymous · Answer

first you gotta find the center so the diameter cuts between (-1,2) and (-1,8) whats the midpoint between those 2 lines.

anonymous · Answer

their mid point is  (-1,5) and distance is 6

anonymous · Answer

will the midpoint be the center??

anonymous · Answer

now you have your h,k

anonymous · Answer

oh thanks, xD

anonymous · Answer

(x+1)^2+(y-5)^2= 9 would be the answer right?

mrnood · Answer

@physicscrap has assumed that the 2 points are on a diameter.

Since the distance between them is 6 THEN you can deduce that the midpoint IS the centre.

IF the radius was for instans 8 then the circle would look lik ethis  (and the question much harder...):
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