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Chemistry 20 Online
OpenStudy (abhisar):

@Abmon98 @Somy

OpenStudy (abhisar):

When mercuric iodide is added to the aqueous solution of potassium iodide, freezing point is raised. Why ?

OpenStudy (abhisar):

Is this a reaction ? 2KI + HgI2 = K2[HgI4]

OpenStudy (abhisar):

I got it !

OpenStudy (abhisar):

Suppose there was 1 molal KI solution. In aqueous solution it will dissociate and form 1 mole K+ and 1 mole I- ions. Now when HgI is added, it forms a stable comlex K2[HgI4]. Now only 1 moles of solute particle are in the solution. depression of freezing point is proportional to moles of solute particles. As number of solute particles is reduced....Freezing point is raised.

OpenStudy (abhisar):

Thank you @mayankdevnani !

OpenStudy (mayankdevnani):

mention not!! @Abhisar bhaiya

OpenStudy (abmon98):

i think because strong ionic bonds are broken

OpenStudy (abhisar):

But then freezing point should decrease.

OpenStudy (abhisar):

\(\sf \Delta T=K_f\times molality\)

OpenStudy (abhisar):

If bonds are broken, then KI-->K+ + I- and HgI -> Hg+ + I-....molality of solutes will increase and hence the freezing point should decrease ?

OpenStudy (abhisar):

There must be something which is decreasing the molality !

OpenStudy (abhisar):

Not able to open the above link !

OpenStudy (abhisar):

Got it ! Thank you @Abmon98 !

OpenStudy (abmon98):

good, your most welcome :D

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