Question

Can someone just check my final answers

Answer 1

Sure post them !

Answer 2

I am typing the equations now just give me a minute!

Answer 3

\[\int\limits_{}^{}(x+1/x^2)^2dx\] original equation find the indefinite integral \[\frac{ x^3 }{ 3 }+2x-\frac{ 1 }{ x }+c\] final answer I got

Answer 4

If we derivate what you got : \[(\frac{ x ^{3} }{ 3 }+2x-\frac{ 1 }{ x }+c)'=\frac{ (x²+1)² }{ x² }\] Which is not exactly what you've been given.

Answer 5

\[\int\limits_{}^{}(x+1/x ^{2})^{2}dx=\int\limits_{}^{}(x ^{2}+2/x+1/x ^{4})dx\]
⌠x²dx = x³/3 + c
⌠(2/x)dx = 2Ln(x) + c
⌠(1/x^4) = -1/(3x³) + c
Add them up to get your final answer.