Tammy is at the dentist's office waiting on her appointment. She notices that the 6-inch-long minute hand is rotating around the clock and marking off time like degrees on a unit circle. Part 1: How many radians does the minute hand move from 1:20 to 1:55? (Hint: Find the number of degrees per minute first.) Part 2: How far does the tip of the minute hand travel during that time? Part 3: How many radians on the unit circle would the minute hand travel from 0° if it were to move 5π inches? Part 4: What is the coordinate point associated with this radian measure?
I have to show all my work as well
@phi
I'll fan and give a medal
@ganeshie8
How many minutes from 1:20 to 1:55 ?
35
you the minute hand takes 60 minutes to go all the way around the circle. what fraction of the whole circle is 35 minutes?
7/12
yes 35/60 which simplifies to 7/12 (divide top and bottom by 5) any idea how many radians in a full circle?
2pi
I think
yes 2pi (roughly 6.28 radians in a circle) now we think: the minute hand moved 7/12 of the way around the circle, so it moved 7/12 of 2 pi radians
1 and 1/6pi
yes, but people probably keep it an improper fraction 7/12 * 2 pi= 14 pi/12 = 7 pi/ 6 radians
btw, if we wanted degrees it would be 7/12 * 360 = 210º (and we could change degrees to radians by multiplying by pi/180 ) we would still get 7 pi / 6 radians
ok on Part 1?
Part 2: How far does the tip of the minute hand travel during that time? you know its 7/12 of the whole way round. find the distance around the circle. i.e find the circumference C= 2 pi r then find 7/12 of C
Oops! Sorry about the wait. How would we go about finding the radius for that?
you read the question carefully? She notices that the 6-inch-long minute hand
*facepalm* I'm sorry. I missed that. In that case, 12pi (for the Circumference), and the distance would be 84pi/12, which simplifies to 7pi. Right?
But wait.. That would theoretically be over 3 hours, right?
That doesn't make sense.
remember that when we find the circumference we are finding the number of inches around the clock, so 7 pi inches (not radians, nor degrees) roughly 22 inches out the all the way around (37.7 inches) btw, I would have done it \[ \frac{7}{12} \cdot 2 \cdot 6 \cdot \pi = \frac{7}{\cancel{12}} \cdot \cancel{12} \cdot \pi = 7 \pi \text{ inches}\] in other words, rather than multiply everything out and then dividing by 12, divide by the "little" numbers... it is easier
For Part 2, we could use the formula \[ s = r \ \theta\] where s is the length of the arc, r is the radius, and theta is the angle *in radians* if you remember that, and use Part 1 (i.e. theta= 7 pi/6 ) you would get s = 6 * 7 pi/6 = 7 pi (same answer!)
Alright! Thank you! So- Part 3
Part 3: How many radians on the unit circle would the minute hand travel from 0° if it were to move 5π inches? I would use the convenient formula s = r * theta can you do that ?
s=6*7pi/6=42pi/6=7pi
that is for Part 2. what about Part 3 ?
and btw, 6*7pi/6 is the same as (6/6) * 7 pi = 1* 7pi = 7pi no need to multiply out 6*7 to get 42. (notice you can do 6/6 in your head)
s=6*5pi
Right? I'm sorry- I'm confused
Which is 30pi
You have to read the question and "match up" the words to the symbols in s= r theta it helps to remember that s is the length of the arc (along the circumference) r is the radius, theta is the angle in radians Part 3: How many radians on the unit circle would the minute hand travel from 0° if it were to move 5π inches? They are asking about *radians*. that means *angle* i.e. they want you to find theta they say the minute hand moves 5 pi inches. Inches is a clue we are moving along an arc. in other words, they are telling you what s is and of course, the radius r is 6 inches
So i need to rearrange the equation to be theta=s/r
Which is theta= 5pi/6
yes, that is one way to proceed. Or you replace the variables with the numbers that you know, and then solve for theta. yes. theta= 5pi/6 radians (you should get in the habit of labeling the units.)
Ok- thank you. We're so close! :)
Part 4: What is the coordinate point associated with this radian measure? can you plot angle 5pi/6 on the unit circle? (I find using degrees is easier)
Couldn't I just pull up a picture of the unit circle and check 5pi/6? I know that's a bit of a shortcut, but that's what the course has shown me thus far
yes, you could. But it is not hard to figure out. 5 pi/6 * 180/pi = 150º |dw:1407692426484:dw|
Join our real-time social learning platform and learn together with your friends!