evaluate f(-2) and f(4). Find the zero of f. f(x)=2-1/2x
Can you post the equation?
@ApollosChariot I just did srry.
Oh, okay, I didn't even see it. Basically what you do is when it says f(-2), you plug -2 into the equation for each x. And for f(4), you plug 4 into the equation for each x
\[f \left( x \right)=2-\frac{ 1 }{ 2 }x\] how do you find the zero of f though @ApollosChariot
You set the equation equal to 0 and then solve for x
|dw:1407691183395:dw|
now it is much more clear find the zero by setting it equal to zero and solve
ok last thing how would I graph -4 which is the zero @satellite73
ok lets take it from the top\[f \left( x \right)=2-\frac{ 1 }{ 2 }x\]
put \[2-\frac{ 1 }{ 2 }x=0\] solve for \(x\)
\[2-\frac{1}{2}x=0\\ -\frac{1}{2}x=-2\\ x=-2\times -2=4\]
point on the graph is \((4,0)\)
Why do you think the point is called a "zero" of the graph?
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