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plz help evaluate (3/2)^-3
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are you doing some kind of exam?
na summer homework trying to catch up
ok then
3/2 is 1.5 so 1.5^-3... im pretty sure that you use\[\frac{1 }{x^y }\]
Essentially, you would flip it around. You already have a fraction so this becomes \(\ \sf (\dfrac{3}{2})^{-3} \implies (\dfrac{2}{3})^3 = \dfrac{2^3}{3^3} = \dfrac{8}{27}\)
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ooooooo ok thank you
Yw ^_~
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