A medical screening program administers three independent fitness tests. Of the persons taking the tests, 85% pass test 1, 65% pass test 2, and 50% pass test 3. A participant is chosen at random a) What is the probability that she will pass all 3 tests? b) What is the probability that she will pass at least 2 of the 3 tests?
prob of passing test 1 = 0.85 prob of passing test 2 = 0.65 prob of passing test 3 = 0.65
here the events are all independent so just multiply the individual probabs for part (a)
multiply all 3 together?
yup
okay i got .27625 for that!
ok
how do i find the second?
can you say the probab of not passing test 1
prob of passing test 1 = 0.85 hence prob of not passing test 1 is 1-0.85 =0.15 and similar for the rest tests
so do i find all of those and use them together?
u need to find them but also check what the question asks
hint : prob for passing test 2 and test3 and not tets1 = 0.65*0.5*0.15 =0.04875
1-0.04875?
nope find the probab for apssing test1 and 3 and not test2 find the probab for apssing test1 and 2 and not test3
ahh okay hold on
not passing test 2 would be .35*.85*.5= .14875 not passing test 3 would be .5*.85*.65= .27625
probability that she will pass at least 2 of the 3 tests = (prob for passing test 2 and test3 and not tets1) + (probab for apssing test1 and 3 and not test2)+ (probab for apssing test1 and 2 and not test3) + probability that she will pass all 3 tests
.75?
?
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