Question

Find the derivative: (x)(1-(4/x-3))

Answer 1

(x)(4/(x-3)^2)+1(1-(4/x-3)) right?

Answer 2

It should be -4x/(x-3)^2 + 1(1-(4/x-3))

Answer 3

You just forgot to add the minus sign

Answer 4

Ok thanks! Wait I'll try to solve again.

Answer 5

I still got it without the minus sign.

Answer 6

What is your actual question? I am not getting it..

Answer 7

0-(-4) / (x-3)^2

Answer 8

Find the derivative of the equation.

Answer 9

\[x (1 - \frac{4}{x-3})\]

Answer 10

I'll try to equate it to clarify.

Answer 11

Haha, yes that's it.

Answer 12

Multiply x inside first..

Answer 13

\[1 - (\frac{(x-3) \cdot 4(1) - 4x \cdot 1}{(x-3)^2}) \implies \frac{(x-3)^2 - 4x + 12 + 4x}{(x-3)^2}\]

Answer 14

You can simply cancel 4x with 4x there.. I hope I am getting your question properly.. :)

Answer 15

LOOOOOOOOOOOOOOOOOOOOOOOOOOOOOL
I'm so sorry. I thought it was 1 +4/(x-3)
You are correct

Answer 16

@hopelovelift lol that's alright, those +/- signs are annoying sometimes. Haha
@waterineyes I'm a little lost. lol. I'll show you what I got so far, see if I'm in the right track

Answer 17

\[(x)(\frac{ 4 }{ (x-3)^{2} }) + (1)(1 - \frac{ 4 }{ x-3 })\]

Answer 18

What I got after simplification
(x^2-6x+21)/(x-3)^2

Answer 19

Oh man that's the correct answer. How'd you get that? Haha

Answer 20

So I was wrong in the simplification. lol

Answer 21

Its the same as waterineyes but a bit more simplified
I'll show you, gimme a minute

Answer 22

That is nothing but if you open the brackets for (x-3)^2

Answer 23

And add 12 to it..

Answer 24

\[(x-3)^2 = x^2 + 9 - 6x\]

And add 12 to it.. :)

Answer 25

Simplify it more. I can't be stuffed drawing the rest XD
All you are doing is making the denominator the same.