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Physics 8 Online
OpenStudy (eric_d):

3.

OpenStudy (eric_d):

http://prntscr.com/4boe68

OpenStudy (eric_d):

@Abhisar

OpenStudy (abhisar):

hav u tried it urself ?

OpenStudy (eric_d):

what formula do I need to use

OpenStudy (eric_d):

Based on the diagram, momentum is conserved

OpenStudy (fifciol):

Potential energy of the spring is converted into kinetic energy

OpenStudy (eric_d):

ok..

OpenStudy (abhisar):

but there is no k given

OpenStudy (eric_d):

I think energy of spring = total k.e of both the trolleys

OpenStudy (fifciol):

yes

OpenStudy (abhisar):

yes that's possible

OpenStudy (fifciol):

and you can calculate v of trolley Q by applying conservation of momentum

OpenStudy (abhisar):

yes ! 4\(\times 1.5=3\times V\\ =>V=(4\times 1.5)/3\)

OpenStudy (eric_d):

So, the formula is mu+mv=0

OpenStudy (abhisar):

yes because initially both were at rest

OpenStudy (eric_d):

v=2

OpenStudy (abhisar):

yes....! Now add the KEs of both blocks

OpenStudy (eric_d):

10.5 J

OpenStudy (eric_d):

Thank you @Abhisar and @Fifciol

OpenStudy (abhisar):

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