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Mathematics 20 Online
OpenStudy (1018):

Find the derivative:

OpenStudy (anonymous):

Hooray!! I have found it.. :P

OpenStudy (1018):

\[\sqrt[4]{9-x^2}\]

OpenStudy (1018):

Hahaha! Wait!

OpenStudy (1018):

Thank God you're here. lol

OpenStudy (anonymous):

You need to apply Chain Rule here.. :)

OpenStudy (anonymous):

you must know this: \[\huge \sqrt[n]{a} = (a)^\frac{1}{n}\]

OpenStudy (1018):

Step by step please. Haha

OpenStudy (1018):

Yes, I'm familiar. :)

OpenStudy (1018):

so, (9-x^2)^1/4 right?

OpenStudy (anonymous):

So, please write your expression in this form first.. :)

OpenStudy (1018):

I'm stuck there. Haha

OpenStudy (1018):

\[(9-x^2)^{\frac{ 1 }{ 4}}\]

OpenStudy (anonymous):

You must now know that : \[\large \frac{d}{dx}(f(x)^m) = m \cdot (f(x)^{m-1}). f'(x)\]

OpenStudy (anonymous):

Just try to implement it here...

OpenStudy (1018):

oh yeeeah... wait, is it now:\[\frac{ 1 }{ 4}(9-x^2)^{\frac{ -3 }{ 4}}\]

OpenStudy (anonymous):

Have you forgot anything?? Yes, upto here you are right but it is still incomplete.. :P

OpenStudy (1018):

How 'bout this? : \[\frac{ 1 }{ 4}(9-x^2)^{\frac{ -3 }{ 4}}(-2x)\]

OpenStudy (anonymous):

You are getting it right.. :P

OpenStudy (anonymous):

Good... :)

OpenStudy (1018):

Is that correct? Haha, so what now? I just simplify?

OpenStudy (anonymous):

Yes you can simplify it..

OpenStudy (anonymous):

2 and 4 you can simplify.. You can again use : \[\large (a)^{\frac{-1}{n}} = \frac{1}{\sqrt[n]{a}}\]

OpenStudy (1018):

I got it! Haha. Thaaanks again!

OpenStudy (1018):

Hey, I have a question. Is there a name for that rule? The one I best response-d.

OpenStudy (anonymous):

Which rule??

OpenStudy (1018):

Oh, sh... I thought I'd only be best-ing one response. lol. The one with where you have to multiply it by f'(x)

OpenStudy (anonymous):

Chain rule I said already... :)

OpenStudy (1018):

I only know the part to bring down the coefficient. Oh, ok ok thanks. I'll look into the chain rule again, must've missed it in the lectures. Thanks!

OpenStudy (anonymous):

Actually, from very first problem you are using that rule but you did not know that you were using that rule, Can I show you that??

OpenStudy (1018):

Ok, sure. I know that there's a chain rule, but I thought it was just to cancel this and that.

OpenStudy (anonymous):

Okay tell me what is the derivative of \(e^x\) with respect to x ??

OpenStudy (1018):

\[xe^\] ?

OpenStudy (1018):

\[xe^{x-1}\]

OpenStudy (anonymous):

You have told this to me, I tolerated it, don't go outside and tell everybody that derivative of \(e^x\) is what you have just told, people will make fun of you.. :P

OpenStudy (anonymous):

So, as you are just studying these things so I want to tell you that: \[\frac{d}{dx} (e^x) = e^x\]

OpenStudy (anonymous):

If I have to tell you about these things, it will take time surely..

OpenStudy (1018):

Oh, oh sorry. Wait, I'll just study first my lectures. Thanks again for your help!

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