: An ideal (non-viscous) liquid with a density of p is poured into a cylindrical vessel
with a cross-sectional area of A1 to a level at a height h from the bottom. The bottom has an
opening with a cross-sectional area A2 . Find the time it takes the k=liquid to flow out.
Is the terminology 'k=liquid' significant?
What strategy should I apply to this problem?

Question

: An ideal (non-viscous) liquid with a density of p is poured into a cylindrical vessel 
with a cross-sectional area of A1 to a level at a height h from the bottom. The bottom has an 
opening with a cross-sectional area A2 . Find the time it takes the k=liquid to flow out. 
Is the terminology 'k=liquid' significant?
What strategy should I apply to this problem?

anonymous · Answer

This one has me stumped too. Working through solution, I can't see how formulae 1.4 and 1.5 are derived. Looking forward to responses!

anonymous · Answer

Hi Alyssana. I think the question is "Find the time it takes the liquid to flow out." and this "k=" is not from this question. As to what strategy to use, watch this video, it might help you : https://www.youtube.com/watch?v=3gxNrc_EEN8 to JamieBellinger: I think equations 1.4, 1.5 and 1.6 are powers of dimensions of L, M and T respectively. Since our equality is [T] = ... we do not have mass and length dimensions (so the powers of L and M are zero) and the power of time dimension must satisfy [T]^1=[T^-2]^X => 1 = -2X .