Question

How large in N is the electrostatic repulsion between two protons a distance d = 6.7 fm apart in a nucleus?

Answer 1

whats N? newton?

Answer 2

F=kQQ'/r^2..Q and Q' are the two charges charge of a proton here...
r is the distance between them( strictly speaking between their centres)
k is a constant: 8.98*10^9

Answer 3

btw Q=Q' here..so u can write Q^2....Q being the charge on a proton

Answer 4

do you know what the charge would be?

Answer 5

ohhh nvm!

Answer 6

if i recall correctly..its 1.62*10^-19C

Answer 7

So I did F=8.98E9*(1.6E-19^2)/(6.7^2)=5.12E-30 but it says its wrong

Answer 8

6.7 fm sweetheart...its 6.7*10^-15 i guess

Answer 9

wats the answer?

Answer 10

@witthan1

Answer 11

One sec sorry

Answer 12

5.12 thank you!