how do i find the range and the min and max values?
13−20x−x^2−3x^4

Question

how do i find the range and the min and max values?
13−20x−x^2−3x^4

amistre64 · Answer

calculus helps

amistre64 · Answer

from algebra, we know that a -x^4 graph does what?

anonymous · Answer

goes through the x-axis 4 times?

amistre64 · Answer

at least 4 times,  but in terms of range, it opens downward, so the max will approach -inf

anonymous · Answer

okay

amistre64 · Answer

the min, we should take a derivative

anonymous · Answer

i havent learned how to do that yet. this is from a summer packet that i have to do in preparation for AP calculus

amistre64 · Answer

13−20x−x^2−3x^4

derive to get

-20-2x-12x^3

and determine when 

-20-2x-12x^3=0

amistre64 · Answer

your packet doesnt tell you how to find a derivative?  or a min/max of a function?

anonymous · Answer

No, i havent learned derivatives yet, is there any other way i could approach this?

amistre64 · Answer

trial and error ..

anonymous · Answer

what if i just graphed it?

amistre64 · Answer

if you are able to just graph it, then yeah that would be fine

anonymous · Answer

okay thank you

amistre64 · Answer

-20-2x-12x^3=0

-2(10+x+6x^3) = 0

10+x+6x^3 = 0 has no positive roots and 1 negative root, which would have to be a double so im thinking the graph is something like:

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