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Mathematics 7 Online
OpenStudy (naga447):

Can anyone explain what I need to do to solve this question? I will give a medal to who ever helps

OpenStudy (naga447):

OpenStudy (amistre64):

spose we had something like:\[3^3=3*3*3\] well, when we have something like (3^3)^4 we get:\[3^3*3^3*3^3=3*3*3*3*3*3*3*3*3*3*3*3=3^{12}\]

OpenStudy (amistre64):

so one of the properties you need to remember is that exponents of an exponent result in multiplicaiton of exponents:\[(b^n)^k=b^{nk}\]

OpenStudy (amistre64):

the next property is simply how to turn a fractional exponent into a radical, which is simply rooting to the denominator

OpenStudy (anonymous):

well ya got to it first but yeah \[\large (x^m)^n = x^{m*n}\]

OpenStudy (amistre64):

\[\large b^{n/d}=\sqrt[d]{b^n}\]

OpenStudy (amistre64):

my (3^3)^4 example is missing a 3^3 :/

OpenStudy (naga447):

To be honest I don't understand I know how to use the equation but I just couldn't figure out what I have to do with 3/5^4

OpenStudy (amistre64):

mutiply the exponents first: what is 3/4 * 2/3 ?

OpenStudy (naga447):

that would be 1/2

OpenStudy (amistre64):

then we are looking for 5^(1/2) in radical form

OpenStudy (amistre64):

2rt(5^1) 2rt is normally written as sqrt so: sqrt(5)

OpenStudy (amistre64):

2rt = sqrt 3rt = cbrt 4rt, 5rt, 6rt, are just written as n rt

OpenStudy (naga447):

\[\sqrt[2]{5}\] this should be it then right?

OpenStudy (amistre64):

yes, but in this case that little 2 is not usually written in since \(\sqrt[2]{...}=\sqrt{...}\)

OpenStudy (naga447):

Okay that makes sense :] thank you!

OpenStudy (amistre64):

good luck ;)

OpenStudy (naga447):

Thanks!

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