Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

what is the axis of symmetry for f(x)=-2(x-4)^2+2

OpenStudy (jdoe0001):

hmmm what's its vertex anyway?

OpenStudy (anonymous):

axis of symmetry : x=h y= -a(x-h)^2 +k this formula sheet will help you set for life with basic conics http://www.jfkcougars.org/ourpages/auto/2013/2/5/43231143/Conics-Formula-Sheet.pdf

OpenStudy (anonymous):

yeah but i need help with the steps

OpenStudy (anonymous):

step 1. find h

OpenStudy (anonymous):

h=4

OpenStudy (anonymous):

yes, axis of symmerty is 4 write as x=4

OpenStudy (jdoe0001):

well... can you get the vertex off the equation... notice is in vertex form already http://www.mathwarehouse.com/geometry/parabola/images/standard-vertex-forms-thumb.png

OpenStudy (anonymous):

so the vertex would be 4,2

OpenStudy (anonymous):

yes, x of vertex is 4 x=4 is the equation of axis of symmetry

OpenStudy (anonymous):

ok but how do i explain how i got that to my teacher.

OpenStudy (anonymous):

i get that the answer is 4 but idk how to explain how i got it

OpenStudy (anonymous):

I'd say something like "When a vertical line runs through the center of the parabola, it divides the parabola into two symmetric halves. Such line is called axis of symmetry. Since we know that axis of symmetry is straight and vertical, it would have no slope. the equation would be x= a value. Now that we analyze the equation, the center is at (4,2). x=4 would be the only vertical line that runs through the vertex of the equation. Therefore this is the axis of symmetry of f(x)" You can shorten it. It's lengthy and all in my words.

OpenStudy (anonymous):

thank you so much! that was what i was looking for. you are a big help thank you (:

OpenStudy (anonymous):

anytime :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!