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OpenStudy (anonymous):
doesn't this have to do with logarithms and like e^x?
OpenStudy (tylerd):
ah ok your doing that, this one you can do in your head but one sec
OpenStudy (anonymous):
Sorry, I haven't done this in a while, but thanks
OpenStudy (tylerd):
will let bibby take it from here
OpenStudy (anonymous):
Thank you
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OpenStudy (bibby):
You can take the ln of both sides such that\[\large \frac{1}{5}^x = \frac{1}{25}\]\[\large ln(\frac{1}{5}^x) = ln(\frac{1}{25})\]\[\large xln{(\frac{1}{5})} = ln(\frac{1}{25})\]\[\large x = \frac{ln(\frac{1}{25})}{ln{(\frac{1}{5})}}\]
x=2
OpenStudy (anonymous):
Thanks! I understand it now
OpenStudy (tylerd):
you can also use logs doesnt have to be LN
OpenStudy (tylerd):
er log with base 10
OpenStudy (bibby):
I don't remember how logs work, but I do remember that when you take the ln of something with a power it comes out as a coefficient