(1/5)^x = 1/25
Help? I need to know how to do this. Thanks
Can you show how to do it?
er sorry 2
Can you show me how to do it? thanks
\[(\frac{ 1 }{ 5 })^2 = \frac{ 1^2 }{ 25 }\] 1^2=1 so
doesn't this have to do with logarithms and like e^x?
ah ok your doing that, this one you can do in your head but one sec
Sorry, I haven't done this in a while, but thanks
will let bibby take it from here
Thank you
You can take the ln of both sides such that\[\large \frac{1}{5}^x = \frac{1}{25}\]\[\large ln(\frac{1}{5}^x) = ln(\frac{1}{25})\]\[\large xln{(\frac{1}{5})} = ln(\frac{1}{25})\]\[\large x = \frac{ln(\frac{1}{25})}{ln{(\frac{1}{5})}}\] x=2
Thanks! I understand it now
you can also use logs doesnt have to be LN
er log with base 10
I don't remember how logs work, but I do remember that when you take the ln of something with a power it comes out as a coefficient
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