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Mathematics 8 Online
OpenStudy (anonymous):

(1/5)^x = 1/25

OpenStudy (anonymous):

Help? I need to know how to do this. Thanks

OpenStudy (anonymous):

Can you show how to do it?

OpenStudy (tylerd):

er sorry 2

OpenStudy (anonymous):

Can you show me how to do it? thanks

OpenStudy (tylerd):

\[(\frac{ 1 }{ 5 })^2 = \frac{ 1^2 }{ 25 }\] 1^2=1 so

OpenStudy (anonymous):

doesn't this have to do with logarithms and like e^x?

OpenStudy (tylerd):

ah ok your doing that, this one you can do in your head but one sec

OpenStudy (anonymous):

Sorry, I haven't done this in a while, but thanks

OpenStudy (tylerd):

will let bibby take it from here

OpenStudy (anonymous):

Thank you

OpenStudy (bibby):

You can take the ln of both sides such that\[\large \frac{1}{5}^x = \frac{1}{25}\]\[\large ln(\frac{1}{5}^x) = ln(\frac{1}{25})\]\[\large xln{(\frac{1}{5})} = ln(\frac{1}{25})\]\[\large x = \frac{ln(\frac{1}{25})}{ln{(\frac{1}{5})}}\] x=2

OpenStudy (anonymous):

Thanks! I understand it now

OpenStudy (tylerd):

you can also use logs doesnt have to be LN

OpenStudy (tylerd):

er log with base 10

OpenStudy (bibby):

I don't remember how logs work, but I do remember that when you take the ln of something with a power it comes out as a coefficient

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