Question

CHECK MY ALG 2 WORK!!! HELP ASAPP!!!!

Answer 1

The function f(x) = 16(5)x represents the growth of a bee population every year in a remote swamp. Jennifer wants to manipulate the formula to an equivalent form that calculates two times a year, not just once a year. Which function is correct for Jennifer's purpose, and what is the new growth rate? (5 points)

f(x) = 16(5)x; growth rate 500%
f(x) = 16(5)2x, growth rate 8%
f(x) = 16(2.24)x; growth rate 8%
f(x) = 16(2.24)2x; growth rate 24%


Is the answer D?

Answer 2

@study100

Answer 3

well I found the best explanations for this question. could not do better
http://openstudy.com/study#/updates/532dfbd3e4b09ca30f90848f

Answer 4

notice --> represents the growth of a bee population every year in a remote swamp. <---
that's every year

so let's say "x" is 1 year... so we end up with \(\bf f(x) = 16(5)^{\color{brown}{ x}}\qquad f(x) = 16(5)^{\color{brown}{ 1}}\)

now we want to find out the population in 6months.... how much is 6months of 1 year?

Answer 5

1/2

Answer 6

.5x

Answer 7

@jdoe0001

Answer 8

ahh... what we do to find out how much it has grown in 6months, is that we simply "split" the "x" in 2 pieces 1/2 + 1/2 = 1 so 1/2x thus \(\large \bf {
f(x) = 16(5)^{\color{brown}{ x}}\qquad f(x) = 16(5)^{\color{brown}{ \frac{1}{2}}x}\implies f(x) = 16(5^{\color{brown}{ \frac{1}{2}}})^x
\\ \quad \\
recall\implies a^{\frac{{\color{blue} n}}{{\color{red} m}}} = \sqrt[{\color{red} m}]{a^{\color{blue} n}}\quad thus
\\ \quad \\
f(x) = 16(5^{\color{brown}{ \frac{1}{2}}})^x\implies f(x) = 16(\sqrt[2]{5^1})^x
}\)

Answer 9

so... that's Jennifer's equation

Answer 10

@jdoe0001 first time heard of Jennifer's equation xDD

Answer 11

so the answer would be B? @jdoe0001 @study100

Answer 12

hehehe

Answer 13

well... what.... did you get for the equation once getting the root?

Answer 14

ughhhhhh

Answer 15

ummm

Answer 16

24? idek man i'm sorry this is confusing me @jdoe0001

Answer 17

so close! try again >.<

use your calculator to find \[\sqrt{5}\]

Answer 18

2.236

Answer 19

and that rounds to 2.24

Answer 20

\(\bf f(x) = 16(5^{\color{brown}{ \frac{1}{2}}})^x\implies f(x) = 16(\sqrt[2]{5^1})^x\implies f(x)=16(\sqrt{5})^x
\\ \quad \\
\textit{so... what is }\sqrt{5}\quad then?\approx 2.24\quad thus
\\ \quad \\
f(x)=16({\color{brown}{ \square ?}})^x\)

Answer 21

jdoe gave you the whole equation! now plug in and voila~

Answer 22

24% :)

Answer 23

@jdoe0001

Answer 24

2.24

Answer 25

Which one of these two has the same Jennifer's equation? (like jdoe's answer)
f(x) = 16(2.24)x; growth rate 8%
f(x) = 16(2.24)2x; growth rate 24%

notice the 24% answer choice has the wrong equation

Answer 26

ah I kinda already says 24% is wrong D: dangit

Answer 27

Damn : /

Answer 28

@study100 this is confusing : ///

Answer 29

Wait it's be C!!!

Answer 30

@jdoe0001 @study100

Answer 31

yeah it be C :)

Answer 32

please medal jdoe for this awesome explanation

Answer 33

his*

Answer 34

thank y'all both :)

Answer 35

anytime :)

Answer 36

The answer is NOT C!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 37

good looking @Jon_devries65