Given the exponential equation 2x = 8, what is the logarithmic form of the equation in base 10?
WAIT actually I might have got it, so could someone just check my answer?
Is it log(10) 8 / log(10) 2????
\(\normalsize\color{blue}{ 2^x=8}\) The relation is \(\normalsize\color{black}{ A^B=C~~~~~~~~→~~~~~~\log_AC=B}\)
\(\normalsize\color{blue}{ 2^x=8~~~~~~~→~~~~~?}\) you tell me
log(2)8 = x
Yes, but you need in base of 10, so apply, \(\normalsize\color{blue}{ \log_DC=\huge\frac{Log_{10}C}{Log_{10}D}}\)
exactly, couldn't you apply base of 10 from the beginning?
well, not really, because of the relation, you at first need to have the base 2.
okay, so from there how do you go about switching it into base of 10?
@SolomonZelman
I posed the rule, log(D) C = Log (10) C / Log (10) D
*posted
well, base 10 is just when the base is unspecified anyway
how do you get D though?
@SolomanZelman
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