Question

A spherical balloon is being inflated by a machine that increases the balloon's volume at a steady 1000cc per second. Please show that the balloon's radius after 6.0 sec of inflation is approximately 11.273cm

Answer 1

u have to use the formula dV/dt = 100pi

Answer 2

volume of sphere is V= 4/3 pi r^3
dV/dr = 4 pi r^2

Answer 3

dr/dt = 100pi / 4pi r^2 = 25/ r^2

then you ought to substitute r= 5ft dr/dt = 25/ 25= 1 ft/min

Answer 4

the radius is 5ft, Surface area, A =4pi r^2 dA/dr = 8pi r
soo...
To get dA/dt = dA/dr * dr/dt
dA/dt = 8 pi r * 1 = 8 pi r
then you have to substitute r = 5 ft.
dA/dt = 40pi ft^2 /min

Answer 5

@roger97c u got it ?