Question

Identify the vertical asymptotes of f(x) = quantity x minus 4 over quantity x squared plus 13 x plus 36

Answer 1

Identify the vertical asymptotes of f(x) = quantity x minus 4 over quantity x squared plus 13 x plus 36

Answer 2

@radar

Answer 3

So since it is x that would mean that the denominator is zero
Factoring
it would look like this
(x +4)(x + 9) = 0
( u set both sides equal to zero)
x + 4 = 0
x + 9 = 0
then you just solve :)

Answer 4

\[ \Large
\frac{x-4}{x^2+13x+36} = \frac{x-4}{(x+4)(x+9)}
\]
What values of x will make the denominator zero? Those are the vertical asymptotes.

Answer 5

@alexandermarrero17 ?