Question

NEED ALG 2 HELP ASAP PLEASE!

Answer 1

Here's two of the options as well as the equation.

Answer 2

@math92130 @mathmale @kropot72

Answer 3

Those are the only two choices?

Answer 4

2^y = 5
We know 2^2 = 4 and 2^3 = 8. So y has to be somewhere between 2 and 3, but closer to 2. When x = 5, neither of the two graphs has y a little bigger than 2. There must be a couple of more choices in the answers.

Answer 5

No sorry, let me post the other answers

Answer 6

@aum

Answer 7

@zepdrix

Answer 8

First, make certain you have all four possible answer choices in front of you. I was a bit thrown off because you initially posted only two of the four possible choices.

Let's actually solve the given equation, \[2^y=5\] Please take either the common log (log) or the natural log (ln) of both sides of this equation. What do you get?

Answer 9

Write out the new equation that these actions give you.

Answer 10

log(2) 5 = y @mathmale

Answer 11

@mathmale @zepdrix

Answer 12

Yes, that's correct. Now, which of the graphs shows a value of 5 for x and a value of ln (to the base 2) of 5 for y?

Answer 13

Please note that if you are using the "log to the base 2," that's fine, but you could just as well use ln or log; your final answer will be the same.

Answer 14

Hints:
Each of the graphs has a dot on it. The dot represents a point (x,y) on the logarithmic graph. When x=5, what value would you expect y to have? Use a calculator, if need be, ot find that y-value, and then decide which of the four given graphs is the correct one.

Answer 15

wait okay let me think sry

Answer 16

When x = 5, y = 2? @mathmale

Answer 17

Roughly 2. Yes. So, which graph would give you approx. this same info?

Answer 18

@mathmale the 4th!

Answer 19

Sorry for my slow response. Yes, that 4th graph is the only one that makes sense. Nice work!

Answer 20

@mathmale thanks so much! do you mind helping me on one last problem?

Answer 21

Go ahead and post it (separately from this one, please).

Answer 22

@chris! I don't see your new question posted yet.

Answer 23

@mathmale i'll post it and tag you! thanks :)