Question

For two events M and N, P(M)=0.6, P(N|M)=0.3, P(N|M')=0.2. Find P(M|N')

Answer 1

hi

Answer 2

i said hi

Answer 3

hi! @Gabbar

Answer 4

the second one should be P(N'|M) =0.3, right?

Answer 5

If it is so, using Baye's theorem to find P(M|N')
If it is not, I don't know how to solve. :)

Answer 6

no thats what's confusing me is why it's set up that way

Answer 7

unless its a typo

Answer 8

hihihi, I am useless then. I am sorry. @ganeshie8

Answer 9

is the N' the complement of N?

Answer 10

Another prob problem hsha. you sure like this aren't you? hehe
but seriously probs are pretty amazing stuff

Answer 11

haha im not having too much fun with them

Answer 12

Okay! you should be having fun hehe

Answer 13

okay let's give a shot! P(M/N')=P(N'/M)P(M)/P(N'/M)P(M)+P(N'/M')P(M')
is this how we wrote that thing before?

Answer 14

well this should the thm that oops talked about!

Answer 15

i think it may have been a typo but ill work that out!

Answer 16

So far i got \(\large\frac{P(N' and M)}{P(N' and M)+0.4\times0.7}\)

Answer 17

we need to find that P(N' and M) to get this hehe

Answer 18

I guess there is not typo you just have to find a way through this!

Answer 19

Any Ideas! more minds are always better hehe. i might be missing something that you guys
paid attention to

Answer 20

i based this if N' is the complement of N

Answer 21

so N'=0.7 right?

Answer 22

where did you got that?
0.7 is complement of P(N' given M') not P(N')
apparently we don't have P(N) so no P(N') either hehe

Answer 23

ahh nevermind i was getting it from P(N|M)

Answer 24

well that's the complement of P(N' given M') that's why it 0.7

Answer 25

"0.7 is complement of P(N' given M') not P(N')"
Actually what i said here is not true
it is the opposite i meant the complement for P(N/M)

Answer 26

Anyways we need something to get that P(N and M')

Answer 27

we need to find P(N) right?

Answer 28

I'm looking for P(n) to get P(n')
we want to get P(N' and M) correction for the line i made earlier

Answer 29

Apparently we have P(N/M')=0.2

Answer 30

so P(N/M')=P(N)P(M')/P(M')=0.2
hence P(N)=0.2 So P(N')=1-0.2=0.8

Answer 31

does that sound fine?

Answer 32

we already have P(M)
so P(N' and M)=P(N')P(M)=0.8\(\times\)0.6=0.48

Answer 33

\(\huge \frac{0.48}{0.48+0.4\times0.7}\)

Answer 34

I'm not sure im doing this good hehe. i might be used some wrong steps xD

Answer 35

ganesh is this P(N'/M') complement of P(N/M)
not sure that's true!

Answer 36

Actually we still have to ask are we dealing with independent events or not?

Answer 37

yes bayee's theorem works :) we may use contingency table :

Answer 38

Oh that pretty good, never used such table ^_^

Answer 39

filling in the given info : ` P(M)=0.6, P(N|M)=0.3, P(N|M')=0.2.`