Question

determine the oxidation number of phosphorous in PO43-

Answer 1

\[\large \bf PO_4^{3-}\]
We know that oxidation no.of oxygen is -2(generally/average)

Let the oxidation no.of phosphorus be x.
Therefore,we get

\[\large \bf Sum~of~total~oxidation~no.=Total~charge\]
so,
\[\large \bf x+4(-2)=-3\]
\[\large \bf x-8=-3\]
\[\large \bf x=+5\]

Hence,Oxidation no.of phosphorus is +5.

Answer 2

and also @madisondurrence
\[\huge \bf \color{red}{Welcome}~\color{blue}{To}~\color{green}{OpenStudy}\]