Question

Factor completely 56a2b3 - 35ab.

7ab(8ab2 - 5)

7a(8b2 - 5ab)

Prime

7a(8ab3 - 5b)

Answer 1

@midhun.madhu1987

Answer 2

\[56a ^{2}b ^{3}-35ab\]
Find what is common in both...it is 7ab
\[7ab(8ab ^{2}-5)\]

Answer 3

thanks

Answer 4

Factor completely -7x2 + 14x – 21.

-1(x2 - 14x + 21)

-7x(x2 - 2x + 3)

-7(x2 + 2x - 3)

-7(x2 - 2x + 3)

Answer 5

Find what is common...it is -7
\[-7(x ^{2}-2x+3)\]

Answer 6

actor completely 6x4y3 + 21x3y2 - 9x2y.

3xy(2x3y2 + 7xy - 3x)

3x2y(2x2y2 + 7xy - 3)

3x2y3(2x2 + 7xy - 3)

3x2y(2x2y + 7xy - 3y)

Answer 7

Try and tell me what you get

Answer 8

b

Answer 9

That is correct

Answer 10

thanks

Answer 11

U welcome :)

Answer 12

Determine the factors of a2b + 2a2 + 3b + 6.

(b + 3)(a2 + 2)

(b + 2)(a2 + 3)

(ab + 2)(a + 3)

(ab + 3)(a + 2)

Answer 13

what is your answer?

Answer 14

c

Answer 15

b?

Answer 16

i used the distrubutive preoperty

Answer 17

yes, it is b

Answer 18

thanks ok couple more

Answer 19

Select the factors of ax - 2ay + 3bx - 6by.

(a + 2b)(x - 3y)

(a - 2b)(x + 3y)

(a + 3b)(x - 2y)

(a - 3b)(x + 2y)

Answer 20

c is my answer

Answer 21

Take common factor from first 2 and then last two...

Answer 22

Factor completely 2x3 + 14x2 + 4x + 28.

2(x3 + 7x2 + 2x + 14)

(2x + 14)(x2 + 2)

2[(x + 7)(x2 + 2)]

(x + 7)(2x2 + 4)

Answer 23

Here also take common factor from first 2 and then last two...

Answer 24

D?